Hello Guys,

My solution to the question below works with positive numbers but fail when a negative is caught. For example [-3,0,1,-3,1,1,1,-3,10,0] returns true but mine return false. How do I resolve this ?

Given an array of integers `arr`

, return `true`

if the number of occurrences of each value in the array is **unique** , or `false`

otherwise.

**Example 1:**

**Input:** arr = [1,2,2,1,1,3] **Output:** true **Explanation:** The value 1 has 3 occurrences, 2 has 2 and 3 has 1. No two values have the same number of occurrences.

**Example 2:**

**Input:** arr = [1,2] **Output:** false

**Example 3:**

**Input:** arr = [-3,0,1,-3,1,1,1,-3,10,0] **Output:** true

```
func uniqueOccurrences(_ arr: [Int]) -> Bool {
var result = [Int:Int]()
let numbers = Set(arr)
for nums in arr{
if let value = result[nums]{
result[nums] = value+1
}
else{
result[nums] = 1
}
}
print(result)
for k in result.values{
if numbers.contains(k) && k >= 2 {
return true
}
}
return false
}
uniqueOccurrences([1,2,3,45,6,7,8,9,9,])
```