The following should result in a compile error:
var x:Int? = 5
var y:Int?
y = x! // compiler error, unwrapping is redundant
The unnecessary unwrapping gives the wrong impression about the type of y — namely that it is Int.
Joe_Groff
(Joe Groff)
2
The following should result in a compile error:
var x:Int? = 5
var y:Int?
y = x! // compiler error, unwrapping is redundant
The unnecessary unwrapping gives the wrong impression about the type of y — namely that it is Int.
The compiler doesn't know this. You gave x type 'Int?', not 'Int'.
-Joe
···
On Dec 9, 2015, at 6:31 AM, Amir Michail via swift-evolution <swift-evolution@swift.org> wrote:
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https://lists.swift.org/mailman/listinfo/swift-evolution
The following should result in a compile error:
var x:Int? = 5
var y:Int?
y = x! // compiler error, unwrapping is redundant
The unnecessary unwrapping gives the wrong impression about the type of y — namely that it is Int.
The compiler doesn't know this. You gave x type 'Int?', not 'Int’.
It knows this because x! has type Int and y has type Int?. So the unwrapping is unnecessary prior to the assignment to y. You should have just written “y = x”.
···
On Dec 9, 2015, at 12:13 PM, Joe Groff <jgroff@apple.com> wrote:
On Dec 9, 2015, at 6:31 AM, Amir Michail via swift-evolution <swift-evolution@swift.org> wrote:
-Joe
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swift-evolution mailing list
swift-evolution@swift.org
https://lists.swift.org/mailman/listinfo/swift-evolution
Joe_Groff
(Joe Groff)
4
Ah, I see what you're saying. This seems like a reasonable warning to add to the compiler; I don't think it requires a formal language change. Got time to file a bug requesting this?
-Joe
···
On Dec 9, 2015, at 3:20 PM, Amir Michail <a.michail@me.com> wrote:
On Dec 9, 2015, at 12:13 PM, Joe Groff <jgroff@apple.com> wrote:
On Dec 9, 2015, at 6:31 AM, Amir Michail via swift-evolution <swift-evolution@swift.org> wrote:
The following should result in a compile error:
var x:Int? = 5
var y:Int?
y = x! // compiler error, unwrapping is redundant
The unnecessary unwrapping gives the wrong impression about the type of y — namely that it is Int.
The compiler doesn't know this. You gave x type 'Int?', not 'Int’.
It knows this because x! has type Int and y has type Int?. So the unwrapping is unnecessary prior to the assignment to y. You should have just written “y = x”.