Is there any easy way to get the actual type behind the opaque type?

Using Swift
1

How to know whatt some View actually is from Xcode? Something similar to option-click that shows me the actual type.

                                           //vvvv I need to put the real type here
class HostingController: WKHostingController<ContentView> {
                      //vvv and the real type here
    override var body: ContentView {
        // Cannot convert return expression of type 'some View' to return type 'ContentView'
        return ContentView().environmentObject(ThemeColor())    // what type does .environmentObject() return?
    }
}

So ContentView().environmentObject(ThemeColor()) is some View, I need its type so I can replace ContentView generic type here for it to compile

2

If you want to know the static type:

func tellMeTheStaticType<T, U>(_ kp: KeyPath<T, U>) {
    print(U.self)
}
tellMeTheStaticType(\HostingController.body)

If you want to know the dynamic type:

print(type(of: instanceOfHostingController.body))
3

The problem is HostingController doesn't even compile now after adding the .environmentObject() modifier because it's a generic to type ContentView. I just realize even if I know the real type return from .environmentObject(), it doesn't help me in this situation. I'll just do this:

struct ContentView: View {
    var body: some View {
        MyApp()        // <== MyApp was ContentView
            .environmentObject(ThemeColor())
    }
}

Phone app SceneDelegate is not generic so you can simply attach .environmentObject(), but watch app HostingController is generic to ContentView so you cannot add any modifier to ContentView().

Edit: if I know the actual type, I can force cast as! So it does help.