Find not containing two character strings

Using Swift
1

Hi everyone,
Would someone be able to help me understand how to approach or find the solution to this question? I’d really appreciate any guidance.
Question: Find strings that don't contain the strings ab, cd, pq, or xy, even if they are part of one of the other requirements.
Input: "zgsnvcdmlfuplrubt" "vlhagaovgqjmgvwq" "ffumlmqwfcsyqpss"
This is how I started.

 func wordsNotIncludingAbCdPqXy(_ input: String) -> Bool {
 
    let vowels: Set<String> = ["ab","cd","pq","xy"]
    print(vowels)
    var result = false

    for string in vowels {
            if !vowels.contains(input) {
                result = true
            }
        }
    return result
}
2 
import Algorithms

extension String {
  var containsConsecutiveLetters: Bool {
    windows(ofCount: 2).contains(
      where: (["ab", "cd", "pq", "xy"] as Set<Substring>).contains
    )
  }
}

https://swiftpackageindex.com/apple/swift-algorithms/1.2.1/documentation/algorithms/swift/collection/windows(ofcount:)

1 Like
3

If I understand you correctly, you want to check if the input contains a vowel. The code you have checks if the vowels set contains the whole input, which is not what you intended.

It looks like a simple logic issue, and you can even (lightly) optimize it. Here is a corrected snippet (but it can be written multiple different ways):

 static let vowels: Set<String> = ["ab","cd","pq","xy"]
 func doesNotContainVowels(_ input: String) -> Bool {
    for vowel in Self.vowels { // or use 'vowels' (replace 'Self.vowels')
            if input.contains(vowel) {
                return false
            }
        }
    return true
 }
1 Like