1

Hi, I was using pow in my code and noticed that it returns decimal type. As I had to further use this value in different calculations, I was looking into converting this to Int type.

I did this by wrapping it with NSDecimalNumber and then Int as follows; Int(NSDecimalNumber(decimal: pow(10,i))).

However, this is giving me a warning

warning: 'init(_:)' is deprecated: replaced by 'init(truncating:)'

and a note during compilation and execution

note: use 'init(truncating:)' instead
                recreated_n += digits[i-len]*Int(NSDecimalNumber(decimal: pow(10,i)))
                                             ^
                                                 truncating:

I just wanted know if there's a better way to do this.

Thanks

2

There's more than one pow function, but the only one that takes an Int as its second argument is

func pow(_ x: Decimal, _ y: Int) -> Decimal

So assuming you want the result to be an Int and your i is an Int in the range 0 ... 18, you can do eg the following (using the pow that takes two Doubles):

let tenToThePowerOfI = Int(pow(10, Double(i)))

Note that 1019 is greater than Int.max so depending on your actual use case, this might not be what you want.

1 Like
3

pow is heavily overloaded. There are overloads that don't return a decimal:

public func pow(_ lhs: Float, _ rhs: Float) -> Float
public func pow(_ lhs: Float80, _ rhs: Float80) -> Float80
public func pow(_: Double, _: Double) -> Double
public func pow(_ lhs: CGFloat, _ rhs: CGFloat) -> CGFloat
public func pow(_ x: Decimal, _ y: Int) -> Decimal