1

this is my string whaen i print it:

Optional("https://api.github.com/search/repositories?sort=stars&q=language%3A&order=desc&per_page=30&**page=2**; rel="next", https://api.github.com/search/repositories?sort=stars&q=language%3A&order=desc&per_page=30&**page=34**; rel="last"")

and i want to put inside 2 variables :
var next = "page=2"
var last = "page=34"

how can I do it easily?

2

I'm not really sure what you mean with put variables part of string but I guess you can do something like

var next = "page=2"
"https://api.github.com(next)"

3

I want to take from this string:

var str = "Optional("https://api.github.com/search/repositories?sort=stars&q=language%3A&order=desc&per_page=30& page=2 ; rel="next", https://api.github.com/search/repositories?sort=stars&q=language%3A&order=desc&per_page=30& page=34 ; rel="last"")"

but get it from the string and finelly it will be:
var next = "page=2"

4

If you have a URL, the best way to get query items is via URLComponents:

let s = "https://api.github.com/search/repositories?sort=stars&q=language%3A&order=desc&per_page=30&page=2"
let uc = URLComponents(string: s)!
let q = (uc.queryItems ?? []).first {
    $0.name == "page"
}!
print(q.value!)     // prints: 2

There’s lots of force unwraps there, something you’d want to fix unless you can absolutely trust the input data.

Getting a URL from the string you have is a bit tricky, primarily because it’s not clear how you got that string in the first place. Can you explain more about that?

Share and Enjoy

Quinn “The Eskimo!” @ DTS @ Apple

2 Likes
5

I get the string in the link header and i can use this data to know what is the url for the next and last page,

thank you for your answer!

6

This would be more concise (and does less work when optimization is off):

uc.queryItems?.first