Should we be able to specialize a generic type in a method, if that generic type declared in type's definition like here? :
struct Foo<I> {
func bar(i: I) where I: Equatable { } // should this work?
}
As I understand, for concrete instance of foo: Foo<X>, if X is not Equatable, then compiler should prevent us from calling foo.bar(x)
Or, probably, the better way to express this could be :
func bar(i: I & Equatable) { }
or
func bar(i: Any<I, Equatable>) { }
Can't check if it possible now because my compiler crashes because of 'where I:Equatable' text (submitted to bugs.swift.org)
This is IMHO better solved via an extension - it even makes more sense to put together methods whose use is limited only to certain generics constraint:
extension Foo where I: Equatable {
func bar(i: I) {
///
}
}
···
On Jun 20, 2016, at 6:57 PM, Vladimir.S via swift-evolution <swift-evolution@swift.org> wrote:
Should we be able to specialize a generic type in a method, if that generic type declared in type's definition like here? :
struct Foo<I> {
func bar(i: I) where I: Equatable { } // should this work?
}
As I understand, for concrete instance of foo: Foo<X>, if X is not Equatable, then compiler should prevent us from calling foo.bar(x)
Or, probably, the better way to express this could be :
func bar(i: I & Equatable) { }
or
func bar(i: Any<I, Equatable>) { }
Can't check if it possible now because my compiler crashes because of 'where I:Equatable' text (submitted to bugs.swift.org)
_______________________________________________
swift-evolution mailing list
swift-evolution@swift.org
https://lists.swift.org/mailman/listinfo/swift-evolution
Thank you for reply. Yes, seems this could be solved by extension. No other solutions?
But how should I be if I need such a protocol?
protocol P1 {
associatedtype T
func foo(t: T)
func bar(t: T) // where T:Equatable ??
}
I.e. I need to specify T & Equatable for bar in requirements
···
On 20.06.2016 20:03, Charlie Monroe wrote:
This is IMHO better solved via an extension - it even makes more sense to put together methods whose use is limited only to certain generics constraint:
extension Foo where I: Equatable {
func bar(i: I) {
///
}
}
On Jun 20, 2016, at 6:57 PM, Vladimir.S via swift-evolution <swift-evolution@swift.org> wrote:
Should we be able to specialize a generic type in a method, if that generic type declared in type's definition like here? :
struct Foo<I> {
func bar(i: I) where I: Equatable { } // should this work?
}
As I understand, for concrete instance of foo: Foo<X>, if X is not Equatable, then compiler should prevent us from calling foo.bar(x)
Or, probably, the better way to express this could be :
func bar(i: I & Equatable) { }
or
func bar(i: Any<I, Equatable>) { }
Can't check if it possible now because my compiler crashes because of 'where I:Equatable' text (submitted to bugs.swift.org)
_______________________________________________
swift-evolution mailing list
swift-evolution@swift.org
https://lists.swift.org/mailman/listinfo/swift-evolution
Something like this should work:
protocol P1 {
associatedtype T
func foo(t: T)
func bar<U where U == T, U: Equatable>(t: U)
}
···
On Jun 20, 2016, at 8:07 PM, Vladimir.S <svabox@gmail.com> wrote:
Thank you for reply. Yes, seems this could be solved by extension. No other solutions?
But how should I be if I need such a protocol?
protocol P1 {
associatedtype T
func foo(t: T)
func bar(t: T) // where T:Equatable ??
}
I.e. I need to specify T & Equatable for bar in requirements
On 20.06.2016 20:03, Charlie Monroe wrote:
This is IMHO better solved via an extension - it even makes more sense to put together methods whose use is limited only to certain generics constraint:
extension Foo where I: Equatable {
func bar(i: I) {
///
}
}
On Jun 20, 2016, at 6:57 PM, Vladimir.S via swift-evolution <swift-evolution@swift.org> wrote:
Should we be able to specialize a generic type in a method, if that generic type declared in type's definition like here? :
struct Foo<I> {
func bar(i: I) where I: Equatable { } // should this work?
}
As I understand, for concrete instance of foo: Foo<X>, if X is not Equatable, then compiler should prevent us from calling foo.bar(x)
Or, probably, the better way to express this could be :
func bar(i: I & Equatable) { }
or
func bar(i: Any<I, Equatable>) { }
Can't check if it possible now because my compiler crashes because of 'where I:Equatable' text (submitted to bugs.swift.org)
_______________________________________________
swift-evolution mailing list
swift-evolution@swift.org
https://lists.swift.org/mailman/listinfo/swift-evolution
Something like this should work:
protocol P1 {
associatedtype T
func foo(t: T)
func bar<U where U == T, U: Equatable>(t: U)
}
Thank you. Strange, but also can't check this code - compiler crashes on it.
IMO it will be good if we can write just
func bar(t: T & Equatable)
···
On 20.06.2016 21:38, Charlie Monroe wrote:
On Jun 20, 2016, at 8:07 PM, Vladimir.S <svabox@gmail.com> wrote:
Thank you for reply. Yes, seems this could be solved by extension. No other solutions?
But how should I be if I need such a protocol?
protocol P1 {
associatedtype T
func foo(t: T)
func bar(t: T) // where T:Equatable ??
}
I.e. I need to specify T & Equatable for bar in requirements
On 20.06.2016 20:03, Charlie Monroe wrote:
This is IMHO better solved via an extension - it even makes more sense to put together methods whose use is limited only to certain generics constraint:
extension Foo where I: Equatable {
func bar(i: I) {
///
}
}
On Jun 20, 2016, at 6:57 PM, Vladimir.S via swift-evolution <swift-evolution@swift.org> wrote:
Should we be able to specialize a generic type in a method, if that generic type declared in type's definition like here? :
struct Foo<I> {
func bar(i: I) where I: Equatable { } // should this work?
}
As I understand, for concrete instance of foo: Foo<X>, if X is not Equatable, then compiler should prevent us from calling foo.bar(x)
Or, probably, the better way to express this could be :
func bar(i: I & Equatable) { }
or
func bar(i: Any<I, Equatable>) { }
Can't check if it possible now because my compiler crashes because of 'where I:Equatable' text (submitted to bugs.swift.org)
_______________________________________________
swift-evolution mailing list
swift-evolution@swift.org
https://lists.swift.org/mailman/listinfo/swift-evolution
This may change a lot if once existentials proposal gets approved and implemented...
Something like this should work:
protocol P1 {
associatedtype T
func foo(t: T)
func bar<U where U == T, U: Equatable>(t: U)
}
Seems like your suggestion will not work. Doug Gregor : "This should be ill-formed. "bar" isn't actually a generic function. If we want this behavior, we should explicitly support it with "where" clauses on non-generic declarations." (https://bugs.swift.org/browse/SR-1849\)
Checking if there is another solution for this.
···
On 21.06.2016 18:59, Charlie Monroe wrote:
On Jun 21, 2016, at 5:20 PM, Vladimir.S <svabox@gmail.com> wrote:
On 20.06.2016 21:38, Charlie Monroe wrote:
Thank you. Strange, but also can't check this code - compiler crashes on it.
IMO it will be good if we can write just
func bar(t: T & Equatable)
On Jun 20, 2016, at 8:07 PM, Vladimir.S <svabox@gmail.com> wrote:
Thank you for reply. Yes, seems this could be solved by extension. No other solutions?
But how should I be if I need such a protocol?
protocol P1 {
associatedtype T
func foo(t: T)
func bar(t: T) // where T:Equatable ??
}
I.e. I need to specify T & Equatable for bar in requirements
On 20.06.2016 20:03, Charlie Monroe wrote:
This is IMHO better solved via an extension - it even makes more sense to put together methods whose use is limited only to certain generics constraint:
extension Foo where I: Equatable {
func bar(i: I) {
///
}
}
On Jun 20, 2016, at 6:57 PM, Vladimir.S via swift-evolution <swift-evolution@swift.org> wrote:
Should we be able to specialize a generic type in a method, if that generic type declared in type's definition like here? :
struct Foo<I> {
func bar(i: I) where I: Equatable { } // should this work?
}
As I understand, for concrete instance of foo: Foo<X>, if X is not Equatable, then compiler should prevent us from calling foo.bar(x)
Or, probably, the better way to express this could be :
func bar(i: I & Equatable) { }
or
func bar(i: Any<I, Equatable>) { }
Can't check if it possible now because my compiler crashes because of 'where I:Equatable' text (submitted to bugs.swift.org)
_______________________________________________
swift-evolution mailing list
swift-evolution@swift.org
https://lists.swift.org/mailman/listinfo/swift-evolution