SE-0335: Introduce existential `any`

[davdroman (David Roman)]

@ebg

Which compiler flag will enable this warning in Swift 5.6?

There are none (by design):

Finding existentials for `any`

There isn't currently a way to turn on warnings for missing anys in your code. That's intentional; we're working on a lot of generics ergonomics features right now that may change the way programmers update their current use of existential types. A lot of Swift code today uses existential types where it doesn't need to because existential types were the more natural thing to write. With opaque parameters and existential opening for function arguments that's being worked on right now, a lot of c…