Hi,
When access the `dynamicType` of a class inside one of its instance
methods. We should be using `self.dynamicType`. I purpose that the
dynamicType operator can be accessed without the need for the `self`.
So code like the following
class Foo {
static let SomeStaticConstantValue = 5
static func someStaticMethod() {
}
func bar() {
self.dynamicType.someStaticMethod()
print(self.dynamicType.SomeStaticConstantValue)
}
}
can be translated to
class Foo {
static let SomeStaticConstantValue = 5
static func someStaticMethod() {
}
func bar() {
dynamicType.someStaticMethod()
print(dynamicType.SomeStaticConstantValue)
}
}
Best Regards,
Mohamed Afifi
+1 to this. I commonly reference self alone very close to
self.dynamicType when I use the dynamicType keyword, and I dislike the
repetitiveness it brings. If a standalone dynamicType is already
disallowed by the compiler, I don't see a technical reason this cannot
happen, personally. If this can happen, then self should probably still
be required to qualify dynamicType in closure contexts (for
consistency), for example:
class Foo {
let value = 123
func bar() {
dispatch_async(queue, {
print(self.dynamicType.value) // self needed here in this closure
})
}
}
···
On 4/10/2016 5:15 AM, Mohamed Ebrahim Afifi via swift-evolution wrote:
Hi,
When access the `dynamicType` of a class inside one of its instance
methods. We should be using `self.dynamicType`. I purpose that the
dynamicType operator can be accessed without the need for the `self`.
So code like the following
class Foo {
static let SomeStaticConstantValue = 5
static func someStaticMethod() {
}
func bar() {
self.dynamicType.someStaticMethod()
print(self.dynamicType.SomeStaticConstantValue)
}
}
can be translated to
class Foo {
static let SomeStaticConstantValue = 5
static func someStaticMethod() {
}
func bar() {
dynamicType.someStaticMethod()
print(dynamicType.SomeStaticConstantValue)
}
}
Best Regards,
Mohamed Afifi
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