Protocol conformance and `Optional`s

[ylorn]

@DevAndArtist

because T and T? are strictly speaking different types

I honestly thought so too until I run into a problem, and this is the example from my thread where bar1 and bar2 are the same thing:

@ylorn

func bar1<Value>(value: Value) {
    print("value: \(value)")
}

func bar2<Value>(value: Value?) {
    print("value: \(value as Any)")
}

bar1(value: string) // correct
bar2(value: string) // correct, same as previous

bar1(value: optionalString) // correct
bar2(value: optionalString) // correct, same as previous