Why is % not available for floating point numbers?
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On Nov 9, 2017, at 04:51 , Martin R via swift-users <swift-users@swift.org> wrote:
There was a discussion in swift-evolution, starting at
[swift-evolution] [Pitch] 'Double modulo' operator
about adding a "true modulo" operator to the standard library. There were different opinions whether
- such a thing needs to be in the standard library at all, and if yes:
- if it should be an operator or function,
- how it should be named.As far as I know, nothing happened until now. The above posting contains a possible (Swift 3) implementation. In Swift 4 that would be
infix operator %%: MultiplicationPrecedence
func %%<T: BinaryInteger>(lhs: T, rhs: T) -> T {
return (lhs % rhs + rhs) % rhs
}I would probably do (as an operator or as a function)
func %%<T: BinaryInteger>(lhs: T, rhs: T) -> T {
let rem = lhs % rhs // -rhs <= rem <= rhs
return rem >= 0 ? rem : rem + rhs
}with one division instead of two.
Regards, Martin
Am 09.11.2017 um 12:43 schrieb Jens Persson via swift-users <swift-users@swift.org>:
Hi all!
Is there a modulo operation/function in Swift? I want the "true" mathematical modulo (as % in Python), and not remainder (as % in Swift).Do I have to implement this basic mathematical function myself and if so what is the best way to write it (it will be heavily used so I want it to be as fast as possible)?
/Jens
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Rick Mann
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