How can I condition on the size of Int?

Using Swift
4

That's interesting. If possible, we'd ideally suppress the warning since the intention here is pretty clear.

That said, there is an alternative spelling which doesn't generate the warning:

if MemoryLayout<Int>.size == 8 {
    print("64-bit")
} else {
    print("32-bit")
}

This yields the same optimized binary.

3 Likes